Submission #1022810

#	Time	Username	Problem	Language	Result	Execution time	Memory
1022810		vjudge1	Catfish Farm (IOI22_fish)	C++17	0 / 100	1069 ms	2097152 KiB

fish

#include "fish.h"
#include <bits/stdc++.h>

using namespace std;

#define ll long long
#define pb push_back
#define F first
#define S second
#define all(v) v.begin(),v.end()
#define sz(s) (int)s.size()
#define lb lower_bound
#define ub upper_bound

const int MAX=2e5+10;

vector<pair<ll,ll>> y[MAX];
vector<ll> p[MAX];
vector<vector<ll>> dp[MAX];
vector<ll> can[MAX];

ll getSum(int x,ll l,ll r){
    if(l>r)return 0;
    int L=lb(all(y[x]),make_pair(l,0ll))-y[x].begin();
    int R=ub(all(y[x]),make_pair(r+1,0ll))-y[x].begin()-1;
    if(L<=R){
        if(L==0)return p[x][R];
        return p[x][R]-p[x][L-1];
    }
    return 0;
}

long long max_weights(int N, int M, vector<int> X, vector<int> Y,vector<int> W) {
    for(int i=0;i<M;i++){
        X[i]++;
        Y[i]++;
        y[X[i]].pb({Y[i],i});
    }
    for(int i=1;i<=N;i++){
        if(y[i].empty())continue;
        sort(all(y[i]));
        p[i].pb(W[y[i][0].S]);
        for(int j=1;j<sz(y[i]);j++){
            p[i].pb(p[i].back()+W[y[i][j].S]);
        }
    }
    can[0].pb(0);
    can[N+1].pb(0);
    for(int i=1;i<=N;i++){
        can[i].pb(0);
        if(i>0){
            for(auto [x,b]:y[i-1])can[i].pb(x);
        }
        if(i+1<N){
            for(auto [x,b]:y[i+1])can[i].pb(x);
        }
        sort(all(can[i]));
    }
    for(int i=1;i<=N+1;i++){
        dp[i].resize(sz(can[i]));
        for(int j=0;j<sz(dp[i]);j++){
            dp[i][j].resize(sz(can[i-1]));
            for(int k=0;k<sz(can[i-1]);k++){
                dp[i][j][k]=0;
            }
        }
    }
    for(int i=1;i<=N;i++){
        for(int j=0;j<sz(can[i]);j++){
            for(int k=0;k<sz(can[i-1]);k++){
                for(int f=0;f<sz(can[i+1]);f++){
                    ll nxt=dp[i][j][k];
                    {
                        int mx=max(can[i+1][f],can[i-1][k]);
                        nxt+=getSum(i,can[i][j]+1,mx);
                    }
                    dp[i+1][f][j]=max(dp[i+1][f][j],nxt);
                }
            }
        }
    }
    ll ans=0;
    for(int j=0;j<sz(can[N]);j++)ans=max(ans,dp[N+1][0][j]);
    return ans;
}

• Subtask 1: 0 / 3
• Subtask 2: 0 / 6
• Subtask 3: 0 / 9
• Subtask 4: 0 / 14
• Subtask 5: 0 / 21
• Subtask 6: 0 / 17
• Subtask 7: 0 / 14
• Subtask 8: 0 / 16