Submission #1022583

#TimeUsernameProblemLanguageResultExecution timeMemory
1022583avighnaCopy and Paste 3 (JOI22_copypaste3)C++17
20 / 100
3086 ms459088 KiB
#include <bits/stdc++.h> typedef long long ll; int main() { std::ios_base::sync_with_stdio(false); std::cin.tie(nullptr); ll n, a, b, c; std::string s; std::cin >> n >> s >> a >> b >> c; if (std::count(s.begin(), s.end(), 'a') == n) { std::vector<std::vector<ll>> dp(n + 1, std::vector<ll>(n + 1)); // dp[i][j] = the minimum cost to match n - i a's if there are j a's in the // clipboard /* dp[i][j] = min{ dp[i + 1][j] + a, dp[i + j][j] + c (j != 0), dp[0][i] + b (i > j) } */ for (ll j = n - 1; j >= 0; --j) { for (ll i = n - 1; i >= 0; --i) { dp[i][j] = dp[i + 1][j] + a; if (j != 0 and i + j <= n) { dp[i][j] = std::min(dp[i][j], dp[i + j][j] + c); } if (i > j) { dp[i][j] = std::min(dp[i][j], dp[0][i] + b); } } } std::cout << dp[0][0] << "\n"; return 0; } std::vector<std::vector<std::vector<std::vector<ll>>>> dp( n + 1, std::vector<std::vector<std::vector<ll>>>( n + 1, std::vector<std::vector<ll>>( n + 1, std::vector<ll>(n + 1, 1e15)))); // dp[x_beg][x_len][y_beg][y_len] => dp[i][j][k][l] = the minimum cost to // match if the current x is (i, j) and the current y is (k, l) for (ll i = 0; i <= n; ++i) { for (ll j = 0; j <= n; ++j) { dp[0][n][i][j] = 0; } } auto substring = [&](ll _i, ll len) { std::string ans; for (ll i = 0; i < len and i + _i < n; ++i) { ans.push_back(s[i + _i]); } return ans; }; /* dp[i][j][k][l] = min{ dp[i][j + 1][k][l] + a, dp[i][j + l][k][l] + c (iff the string matches), dp[0][0][i][j] + b (if the pair (i, j) > (k, l)) } */ for (ll l = n - 1; l >= 0; --l) { for (ll k = n - 1; k >= 0; --k) { for (ll j = n - 1; j >= 0; --j) { for (ll i = n - 1; i >= 0; --i) { dp[i][j][k][l] = dp[i][j + 1][k][l] + a; if (j == 0) { for (ll m = 0; m < n; ++m) { dp[i][j][k][l] = std::min(dp[i][j][k][l], dp[m][1][k][l] + a); } } if (l != 0 and j + l <= n - i and substring(i, j) + substring(k, l) == substring(i, j + l)) { dp[i][j][k][l] = std::min(dp[i][j][k][l], dp[i][j + l][k][l] + c); } if (i > k or (i == k and j > l)) { dp[i][j][k][l] = std::min(dp[i][j][k][l], dp[0][0][i][j] + b); } } } } } std::cout << dp[0][0][0][0] << "\n"; }
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