Submission #1022203

#TimeUsernameProblemLanguageResultExecution timeMemory
1022203parsadox2Shortcut (IOI16_shortcut)C++17
0 / 100
43 ms94300 KiB
#include "shortcut.h" #include <bits/stdc++.h> using namespace std; const int N = 1e6 + 10; const long long int inf = 1e18; long long n , c , d[N]; long long s[N]; struct NODE{ long long mxp , mxm; long long ans; NODE(){ mxp = mxm = ans = 0; } }; struct SEG{ NODE t[N << 2]; NODE Merge(NODE aa , NODE bb) { NODE res; res.mxp = max(aa.mxp , bb.mxp); res.mxm = max(aa.mxm , bb.mxm); res.ans = max({aa.ans , bb.ans , 1LL * bb.mxp + aa.mxm}); return res; } void Build(int node = 1 , int nl = 0 , int nr = n) { if(nr - nl == 1) { t[node].mxp = d[nl] + s[nl]; t[node].mxm = d[nl] - s[nl]; t[node].ans = 0; return; } int mid = (nl + nr) >> 1 , lc = node << 1 , rc = lc | 1; Build(lc , nl , mid); Build(rc , mid , nr); t[node] = Merge(t[lc] , t[rc]); } NODE Get(int l , int r , int node = 1 , int nl = 0 , int nr = n) { if(r <= nl || nr <= l || r <= l) { NODE emp; emp.mxm = -inf; return emp; } if(l <= nl && nr <= r) { //cout << "WTFFF " << nl << " " << nr << " " << t[node].mxm << endl; return t[node]; } int mid = (nl + nr) >> 1 , lc = node << 1 , rc = lc | 1; return Merge(Get(l , r , lc , nl , mid) , Get(l , r , rc , mid , nr)); } } seg; long long Solve(int a , int b) { auto L = seg.Get(0 , a + 1) , R = seg.Get(b , n); long long res = max({L.ans , R.ans , R.mxp - s[b] + s[a] + L.mxm + min(c , s[b] - s[a])}); //cout << a << " " << b << " " << res << endl; long long tmp = (c + s[a] + s[b]) / 2; int pos = upper_bound(s , s + n , tmp) - s; auto L1 = seg.Get(0 , pos) , L2 = seg.Get(pos , b + 1); if(pos >= a && pos <= b) { //cout << "WTF " << L1.ans << " " << L.mxm << " " << L2.mxm << endl; res = max({res , L1.ans , c + s[b] + s[a] + L.mxm + L2.mxm}); } //cout << a << " " << b << " p1 " << pos << " " << res << endl; tmp = (s[a] + s[b] - c) / 2; pos = upper_bound(s , s + n , tmp) - s; auto R1 = seg.Get(a , pos) , R2 = seg.Get(pos , n); if(pos >= a && pos <= b) res = max({res , R2.ans , c - s[a] - s[b] + R.mxp + R1.mxp}); //cout << a << " " << b << " p2 " << pos << " " << res << endl; for(int i = a ; i < b ; i++) for(int j = i + 1 ; j < b ; j++) res = max(res , min(d[i] + d[j] + s[j] - s[i] , d[i] + d[j] + c + s[b] - s[a] - s[j] + s[i])); //cout << a << " " << b << " " << res << endl; return res; } long long find_shortcut(int nn, std::vector<int> l, std::vector<int> D, int C) { n = nn; c = C; for(int i = 1 ; i < n ; i++) s[i] = s[i - 1] + l[i - 1]; for(int i = 0 ; i < n ; i++) d[i] = D[i]; seg.Build(); long long res = inf; for(int a = 0 ; a + 1 < n ; a++) for(int b = a + 1 ; b < n ; b++) { //cout << a << " " << b << endl; res = min(res , Solve(a , b)); } return res; }
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