Submission #1022048

#	Time	Username	Problem	Language	Result	Execution time	Memory
1022048		mansur	Aliens (IOI16_aliens)	C++17	25 / 100	2081 ms	94548 KiB

aliens

#include "aliens.h"
#include <bits/stdc++.h>

using namespace std;

#define rall(s) s.rbegin(), s.rend()
#define all(s) s.begin(), s.end()
#define sz(s) (int)s.size()
#define s second 
#define f first   

using ll = long long;
using pii = pair<int, int>;
using pll = pair<ll, ll>;

const int N = 2e5 + 5;
const ll inf = 1e18;

long long take_photos(int n, int m, int k, vector<int> r, vector<int> c) {
    vector<pii> s;
    for (int i = 0; i < n; i++) {
        int x = min(r[i], c[i]) + 1;
        int y = max(r[i], c[i]) + 1;
        s.push_back({x, y});
    }
    sort(all(s));
    int mx[n];
    for (int i = 0; i < n; i++) {
        if (i) mx[i] = mx[i - 1];
        else mx[i] = 0;
        mx[i] = max(mx[i], s[i].s);
    }
    ll dp[n + 1][k + 1];
    for (int i = 0; i <= n; i++) {
        for (int j = 0; j <= k; j++) {
            dp[i][j] = inf;
        }
    }
    dp[0][k] = 0;
    for (int i = 0; i < n; i++) {
        int x = (i ? mx[i - 1] : 0);
        x = max(x, s[i].f - 1);
        vector<pii> h;
        for (int j = i; j < n; j++) {
            h.push_back({s[j].s, j});
        }
        sort(rall(h));
        int mn = m + 1, p = n, ok = 1;
        for (int j = 0; j < sz(h); j++) {
            if (ok) {
                ll cost = h[j].f - s[i].f + 1;
                cost *= cost;
                //cout << h[j].f << ' ' << s[i].f << "  ";
                cost -= (x - s[i].f + 1) * 1ll * (x - s[i].f + 1);
                //cout << cost << ' ' << p << ' ' << h[j].s << endl;
                for (int y = 1; y <= k; y++) {
                    dp[p][y - 1] = min(dp[p][y - 1], dp[i][y] + cost);
                }
            }
            int id = h[j].s;
            if (id == i) ok = 0;
            if (s[id].f <= mn) {
                mn = s[id].f;
                p = id;
            }
        }
    }
    ll ans = inf;
    for (int i = 0; i <= k; i++) ans = min(ans, dp[n][i]);
    return ans;
}

• Subtask 1: 4 / 4
• Subtask 2: 12 / 12
• Subtask 3: 9 / 9
• Subtask 4: 0 / 16
• Subtask 5: 0 / 19
• Subtask 6: 0 / 40