Submission #1019084

#	Time	Username	Problem	Language	Result	Execution time	Memory
1019084		Cookie	Uzastopni (COCI15_uzastopni)	C++14	72 / 160	3 ms	888 KiB

uzastopni

#include<bits/stdc++.h>
#include<fstream>
using namespace std;
#define sz(a) (int)a.size()
#define ALL(v) v.begin(), v.end()
#define ALLR(v) v.rbegin(), v.rend()
#define ll long long
#define pb push_back
#define forr(i, a, b) for(int i = a; i < b; i++)
#define dorr(i, a, b) for(int i = a; i >= b; i--)
#define ld double
#define vt vector
#include<fstream>
#define fi first
#define se second
#define pll pair<ll, ll>
#define pii pair<int, int>
#define mpp make_pair
const ld PI = 3.14159265359, prec = 1e-9;;
//using u128 = __uint128_t;
const int cox[4] = {1, 0, -1, 0};
const int coy[4] = {0, -1, 0, 1};
const ll mod = 998244353, pr = 31;
const int mxn = 1e3 + 5, mxs = 3e5 * 50, sq = 500, mxv = 100 + 1;
const int max_iter = 8e4, global_iter = 15e5 + 5;
//const int base = (1 <<18);
const ll inf = 1e9 + 5, neg = -69420, inf2 = 1e14;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
int n;
bitset<mxv>dp[10005][105], pre[10005][105];
int v[mxn + 1];
vt<int>adj[mxn + 1];
void dfs(int s, int p){
    
    for(auto i: adj[s]){
        if(i != p){
            dfs(i, s);
            for(int j = 1; j <= 100; j++){
                for(int k = j; k <= 100; k++){
                    if(dp[i][j][k]){
                        dp[s][j][k] = 1;  
                        
                        for(int l = k + 1; l <= 100; l++){
                            if(pre[s][k + 1][l])dp[s][j][l] = 1;
                        }
                        
                        for(int l = j - 1; l >= 1; l--){
                            if(pre[s][l][j - 1])dp[s][l][k] = 1;
                        }
                       
                    }
                }
            }
            for(int j = 1; j <= 100; j++){
                for(int k = j; k <= 100; k++){
                    pre[s][j][k] = dp[s][j][k]; 
                }
            }
        }
    }

    pre[s][v[s]][v[s] - 1] = pre[s][v[s] + 1][v[s]] = 1;
    for(int i = 1; i <= 100; i++){
        for(int j = i; j <= 100; j++){
            if(i <= v[s] && j >= v[s] && pre[s][i][v[s] - 1] && pre[s][v[s] + 1][j]){
                dp[s][i][j] = 1;
            }else{
                dp[s][i][j] = 0;
            }
        }
    }
}
void solve(){
    cin >> n;
    for(int i = 1; i <= n; i++)cin >> v[i];
    for(int i = 1; i < n; i++){
        int a, b; cin >> a >> b;
        adj[a].pb(b); adj[b].pb(a);
    }
    dfs(1, -1);
    int res = 0;
    for(int i = 1; i <= 100; i++){
        for(int j = i; j <= 100; j++){
           
            res += dp[1][i][j];
        }
    }
    cout << res;
}



signed main(){
    ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
    //freopen("KHONG.inp", "r", stdin);
    //freopen("KHONG.out", "w", stdout);
    int tt; tt = 1;
    while(tt--)solve();
    return(0);
}

• Subtask 1: 72 / 160