Submission #101728

#TimeUsernameProblemLanguageResultExecution timeMemory
101728KCSCCoin Collecting (JOI19_ho_t4)C++14
100 / 100
267 ms6256 KiB
#include <bits/stdc++.h> using namespace std; const int DIM = 100005; int cnt[DIM][3]; vector<int> qry[3], bal[3]; int main(void) { #ifdef HOME freopen("coins.in", "r", stdin); freopen("coins.out", "w", stdout); #endif int n; cin >> n; long long ans = 0; for (int i = 1; i <= n * 2; ++i) { int x, y; cin >> x >> y; if (x < 1) { ans += 1 - x; x = 1; } if (x > n) { ans += x - n; x = n; } if (y < 1) { ans += 1 - y; y = 1; } if (y > 2) { ans += y - 2; y = 2; } ++cnt[x][y]; } for (int i = 1; i <= n; ++i) { for (int j = 1; j <= 2; ++j) { qry[j].push_back(i); for (; cnt[i][j]; --cnt[i][j]) { bal[j].push_back(i); } } // solve as many columns with balls placed on the same line for (int j = 1; j <= 2; ++j) { while (qry[j].size() and bal[j].size()) { int p1 = qry[j].back(), p2 = bal[j].back(); qry[j].pop_back(); bal[j].pop_back(); ans += abs(p1 - p2); } } // solve as many columns with balls placed on the opposite line for (int j = 1; j <= 2; ++j) { while (qry[j].size() and bal[3 - j].size()) { int p1 = qry[j].back(), p2 = bal[3 - j].back(); qry[j].pop_back(); bal[3 - j].pop_back(); ans += abs(p1 - p2) + 1; } } } cout << ans << endl; return 0; }
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...