This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#pragma GCC optimize("O3", "unroll-loops")
#define ll long long
#define int long long
#define pb push_back
#define fi first
#define se second
#define lf (id<<1)
#define rg ((id<<1)|1)
#define md ((l+r)>>1)
#define ld long double
using namespace std;
typedef pair<int,int> pii;
typedef pair<pii, int> ipii;
const int MAXN = 110;
const int MAXA = 110;
const int INF = 1e18+10;
const int LOG = 19;
const int MOD = 1e9+7;
const int SQRT = 450;
const vector<int> NOL = {};
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const vector<int> dx = {1, -1, 0, 0};
const vector<int> dy = {0, 0, 1, -1};
void chmx(int &a, int b){ a = max(a, b); }
int n, m, k;
char c[MAXN][MAXN];
bool dp[MAXN][MAXN][MAXA];
string s;
bool valid(int x, int y){
if(x<1||x>n||y<1||y>m||c[x][y]=='#') return 0;
return 1;
}
signed main(){
// ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
cin >> n >> m >> k;
for(int i=1; i<=n; i++)
for(int j=1; j<=m; j++) cin >> c[i][j];
cin >> s; s = '.'+s;
for(int i=1; i<=n; i++)
for(int j=1; j<=m; j++)
dp[i][j][k+1] = valid(i, j);
for(int id=k; id>=1; id--){
for(int i=1; i<=n; i++){
for(int j=1; j<=m; j++){
if(!valid(i, j)) continue;
if(s[id] == '?'){
for(int pp=0; pp<4; pp++){
int nx = i+dx[pp], ny = j+dy[pp];
if(!valid(nx, ny)) continue;
dp[i][j][id] |= dp[nx][ny][id+1];
}
} else {
int nx = -1, ny = -1;
if(s[id]=='W'){
nx = i, ny = j-1;
if(!valid(nx, ny)) continue;
dp[i][j][id] |= dp[nx][ny][id+1];
} else if(s[id]=='E'){
nx = i, ny = j+1;
if(!valid(nx, ny)) continue;
dp[i][j][id] |= dp[nx][ny][id+1];
} else if(s[id]=='N'){
nx = i-1, ny = j;
if(!valid(nx, ny)) continue;
dp[i][j][id] |= dp[nx][ny][id+1];
} else if(s[id]=='S'){
nx = i+1, ny = j;
if(!valid(nx, ny)) continue;
dp[i][j][id] |= dp[nx][ny][id+1];
}
}
}
}
// cout << id << " kk\n";
// for(int i=1; i<=n; i++)
// for(int j=1; j<=m; j++) cout << dp[i][j][id] << " \n"[j==m];
}
int ANS = 0;
for(int i=1; i<=n; i++)
for(int j=1; j<=m; j++) ANS += dp[i][j][1];
// for(int i=1; i<=n; i++)
// for(int j=1; j<=m; j++) cout << dp[i][j][1] << " \n"[j==m];
cout << ANS << '\n';
}
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