This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define endl '\n'
#define FF first
#define SS second
#define all(a) a.begin(), a.end()
#define mod (ll)(1000000007)
int n, m, q, time_;
int sum;
struct Kind {
int L, R;
int Cur = 0;
};
vector<Kind> V(10916762);
int update(int id, int u, int v, int c, int l, int r) {
if (l > v || r < u) {
return id;
}
if (!id && !(l == 1 && r == m)) {
id = time_++;
}
if (u <= l && r <= v) {
int temp = time_++;
V[temp].L = V[id].L;
V[temp].R = V[id].R;
V[temp].Cur = min(V[id].Cur + c, (int)1e9);
return temp;
}
int md = (l + r) / 2;
int temp = time_++;
V[temp].L = update(V[id].L, u, v, c, l, md + 0);
V[temp].R = update(V[id].R, u, v, c, md + 1, r);
V[temp].Cur = V[id].Cur;
return temp;
}
void get(int id, int u, int v, int l, int r) {
if (!id && !(l == 1 && r == m)) {
id = time_++;
}
if (l > v || r < u) {
return;
}
sum = min(sum + V[id].Cur, (int)1e9);
if (l >= u && r <= v) {
return;
}
int md = (l + r) / 2;
get(V[id].L, u, v, l, md + 0),
get(V[id].R, u, v, md + 1, r);
}
int main() {
ios_base::sync_with_stdio(0);cin.tie(0);
cin >> n >> m;
vector<int> Ind[n + 1];
for (int i = 1; i <= m; i++) {
int a;
cin >> a;
Ind[a].push_back(i);
}
int A[n + 1];
for (int i = 1; i <= n; i++) {
cin >> A[i];
}
vector<int> Head;
cin >> q;
int qq = q;
while (qq--) {
int l, r, x;
cin >> l >> r >> x;
if (l <= r) {
Head.push_back(update((Head.empty() ? time_++ : Head.back()), l, r, x, 1, m));
}
else {
auto temp = update((Head.empty() ? time_++ : Head.back()), l, m, x, 1, m);
Head.push_back(update(temp, 1, r, x, 1, m));
}
}
for (int i = 1; i <= n; i++) {
int l = 0, r = Head.size() - 1, res = -1;
while (l <= r) {
int md = (l + r) / 2;
auto cur = Head[md];
sum = 0;
for (auto pos : Ind[i]) {
get(cur, pos, pos, 1, m);
}
if (sum >= A[i]) {
res = md, r = md - 1;
}
else {
l = md + 1;
}
}
if (res == -1) {
cout << "NIE" << endl;
}
else {
cout << res + 1 << endl;
}
}
}
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