Submission #1014333

#	Time	Username	Problem	Language	Result	Execution time	Memory
1014333		anHiep	Lamps (JOI19_lamps)	C++14	4 / 100	74 ms	68068 KiB

lamp

#include<bits/stdc++.h>
#ifdef LOCAL
#include "D:\debug.h"
#else
#define cebug(...) "Orz_chUoNgnn_khanhtb"
#endif

using namespace std;

#define int long long
#define fi first 
#define se second
#define pb push_back
#define ll long long
#define ii pair<int, int>
#define vi vector<int> 
#define vll vector<ll>
#define vii vector<ii>
#define cd complex<double>
const ll mod = 1e9 + 7;
const ll INF = 1e18L + 5;
const double PI = acos(-1);
const int block = 320;
const int N = 1e6;
int tc, tt = 1;

int n;
string a, b;
int dp[N + 5][4][2];
bool ck(int i, int t) {
    if(a[i] == b[i] && t == 0) return true;
    if(b[i] == '0' && t == 1) return true;
    if(b[i] == '1' && t == 2) return true;
    if(a[i] != b[i] && t == 3) return true;
    return false;
}
void solve() {
    cin>>n>>a>>b;
    for(int i=0; i<=n; i++)
        for(int j=0; j<4; j++)
            for(int k=0; k<2; k++)
                dp[i][j][k] = 1e9;
    a = ']' + a;
    b = '[' + b;
    dp[0][0][0] = 0;
    for(int i=1; i<=n; i++)
        for(int j=0; j<4; j++)
            for(int k=0; k<2; k++) if(ck(i, j)){
                dp[i][j][k] = dp[i - 1][j][k];
                dp[i][j][k] = min(dp[i][j][k], dp[i - 1][j][1 ^ k] + 1);
                for(int h=0; h<4; h++)
                    if(h != j) {
                        dp[i][j][k] = min(dp[i][j][k], dp[i - 1][h][k] + (j != 0));
                        dp[i][j][k] = min(dp[i][j][k], dp[i - 1][h][1 ^ k] + (j != 0) + 1);
                    }
            }
    int ans = 1e9;
    for(int i=0; i<4; i++) {
        ans = min(ans, dp[n][i][0]);
        ans = min(ans, dp[n][i][1] + 1);
    }
    cout<<ans;
}
signed main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0); cout.tie(0);
    // freopen(".INP", "r", stdin);
    // freopen(".OUT", "w", stdout);
    for(int tc=1; tc<=tt; tc++) solve();
    cerr<<"\nTime elapsed: "<<1000.0*clock()/CLOCKS_PER_SEC<<" ms.\n";
    return 0;
}

• Subtask 1: 0 / 6
• Subtask 2: 0 / 41
• Subtask 3: 4 / 4
• Subtask 4: 0 / 49