Submission #1012598

#	Time	Username	Problem	Language	Result	Execution time	Memory
1012598		ProtonDecay314	Carnival Tickets (IOI20_tickets)	C++17	11 / 100	1 ms	860 KiB

tickets

/*

*/
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<int, int> pi;
typedef pair<ll, ll> pll;
typedef vector<pi> vpi;
typedef vector<pll> vpll;
typedef vector<bool> vb;
#define IOS ios_base::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr);
#define L(varll, mn, mx) for(ll varll = (mn); varll < (mx); varll++)
#define LR(varll, mx, mn) for(ll varll = (mx); varll > (mn); varll--)
#define LI(vari, mn, mx) for(int vari = (mn); vari < (mx); vari++)
#define LIR(vari, mx, mn) for(int vari = (mx); vari > (mn); vari--)
#define INPV(varvec) for(auto& varveci : (varvec)) cin >> varveci
#define fi first
#define se second
#define pb push_back
#define TCASES int t; cin >> t; while(t--)

#ifndef DEBUG
#include "tickets.h"
#endif

#ifdef DEBUG
vvi ta;
void allocate_tickets(const vvi& a_ta) {
    LI(i, 0, (int)ta.size()) {

        copy(a_ta[i].begin(), a_ta[i].end(), back_inserter(ta[i]));
    }
}
#endif

ll find_maximum(int k, vvi x) {
    int n = x.size(), m = x[0].size();
    vvi talloc;
    LI(i, 0, n) {
        vi tallocr(m, -1);
        talloc.pb(tallocr);
    }

    ll ans = 0ll;

    // Subtask 1
    if(m == 1) {
        vi vals;
        LI(i, 0, n) {
            vals.pb(x[i][0]);
        }

        sort(vals.begin(), vals.end());
        LI(i, 0, n >> 1) {
            ans -= (ll)vals[i];
        }

        LI(i, n >> 1, n) {
            ans += (ll)vals[i];
        }

        LI(i, 0, n) {
            talloc[i][0] = 0;
        }
    }

    allocate_tickets(talloc);

    return ans;
}

#ifdef DEBUG
int main() {
    int n, m, k;
    cin >> n >> m >> k;
    
    vvi x;

    LI(i, 0, n) {
        vi xr(m, 0);
        vi tar;
        INPV(xr);
        x.pb(xr);
        ta.pb(tar);
    }

    cout << find_maximum(k, x) << "\n";

    LI(i, 0, n) {
        LI(j, 0, m) cout << ta[i][j] << " ";
        cout << "\n";
    }

    return 0;
}
#endif

• Subtask 1: 11 / 11
• Subtask 2: 0 / 16
• Subtask 3: 0 / 14
• Subtask 4: 0 / 14
• Subtask 5: 0 / 12
• Subtask 6: 0 / 23
• Subtask 7: 0 / 10