This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define ld long double
#define pll pair<ll,ll>
#define fi first
#define se second
const int maxN=1e5+5;
const ll inf=2e18;
ll n,q,a[maxN+1],k;
struct segment
{
struct Node
{
ll s,mx;
Node()
{
s=0;
mx=-inf;
}
Node(ll S,ll mxn)
{
s=S;
mx=mxn;
}
}sum[4*maxN+1];
Node meg(Node x,Node y)
{
Node res;
res.s=x.s+y.s;
res.mx=max(x.mx,y.mx);
return res;
}
void Build(int x,int low,int high)
{
if(low==high)
{
sum[x]=Node(a[low],a[low]);
return;
}
int mid=(low+high)/2;
Build(2*x,low,mid);
Build(2*x+1,mid+1,high);
sum[x]=meg(sum[2*x],sum[2*x+1]);
}
ll pos,val,l,r;
void Set(int x,int low,int high)
{
if(low==high)
{
sum[x]=Node(val,val);
return;
}
int mid=(low+high)/2;
if(pos<=mid)
{
Set(2*x,low,mid);
}
else Set(2*x+1,mid+1,high);
sum[x]=meg(sum[2*x],sum[2*x+1]);
}
void set_val(ll pos,ll val)
{
this->pos=pos;
this->val=val;
Set(1,1,n);
}
void Update(int x,int low,int high)
{
if(low>r||high<l||sum[x].mx==0)
{
return;
}
if(low==high)
{
sum[x].s/=k;
sum[x].mx/=k;
return;
}
int mid=(low+high)/2;
Update(2*x,low,mid);
Update(2*x+1,mid+1,high);
sum[x]=meg(sum[2*x],sum[2*x+1]);
}
void update_val(ll l,ll r)
{
this->l=l;
this->r=r;
Update(1,1,n);
}
Node get(int x,int low,int high)
{
if(low>r||high<l)
{
return Node(0,-inf);
}
if(low>=l&&high<=r)
{
return sum[x];
}
int mid=(low+high)/2;
Node get1=get(2*x,low,mid);
Node get2=get(2*x+1,mid+1,high);
return meg(get1,get2);
}
Node query(ll l,ll r)
{
this->l=l;
this->r=r;
return get(1,1,n);
}
}st;
int main()
{
//freopen("","r",stdin);
//freopen("","w",stdout);
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin>>n>>q>>k;
for(int i=1;i<=n;i++)
{
cin>>a[i];
}
st.Build(1,1,n);
while(q--)
{
ll s;
cin>>s;
if(s==1)
{
ll pos,val;
cin>>pos>>val;
st.set_val(pos,val);
}
else if(s==2)
{
ll l,r;
cin>>l>>r;
if(k>1)
{
st.update_val(l,r);
}
}
else
{
ll l,r;
cin>>l>>r;
cout<<st.query(l,r).s<<'\n';
}
}
}
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