Submission #1010450

#	Time	Username	Problem	Language	Result	Execution time	Memory
1010450		HishamAlshehri	Growing Vegetables is Fun 4 (JOI21_ho_t1)	C++17	0 / 100	1 ms	4696 KiB

Main

#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>

using namespace std;
//using namespace __gnu_pbds;

#define int long long
#define mod 1000000007
#define base 7001
#define base2 757
// #define pi acos(-1)
#define double long double
//#define ordered_set tree<int, null_type, less<int>, rb_tree_tag,tree_order_statistics_node_update>
//#define ordered_multiset tree<int, null_type, less_equal<int>, rb_tree_tag,tree_order_statistics_node_update>

#pragma GCC optimize("O3,Ofast,unroll-loops")
#pragma GCC target("avx2,sse3,sse4,avx")

constexpr int maxn = 1000001;
const int N = 1 << (int)(ceil(log2(maxn)));

int n, a[maxn], b[maxn];
int prf[maxn][3], suf[maxn][3];

signed main()
{
    cin.tie(0) -> sync_with_stdio(0);
    cin >> n;
    for (int i = 1; i <= n; i++)
        cin >> a[i];
    for (int i = n; i >= 1; i--)
    {
        b[i] = a[i];
        suf[i][0] = suf[i + 1][0];
        suf[i][2] = max((a[i + 1] + 1 - a[i]) - suf[i + 1][2], 0ll);
        suf[i][0] += suf[i][2];
        suf[i][1] = a[i] + max(a[i + 1] + 1 - a[i], 0ll);
        a[i] += max(a[i + 1] + 1 - a[i], 0ll);
    }
    for (int i = 1; i <= n; i++)
    {
        a[i] = b[i];
        prf[i][0] = prf[i - 1][0];
        prf[i][2] =  max((a[i - 1] + 1 - a[i]) - prf[i - 1][2], 0ll);
        prf[i][0] += prf[i][2];
        prf[i][1] = a[i] + max(a[i - 1] + 1 - a[i], 0ll);
        a[i] += max(a[i - 1] + 1 - a[i], 0ll);
    }
    int mn = INT_MAX;

    // for(int i = 0; i < n; i++)
    // {
    //     cout << suf[i + 1][0] << " " << prf[i + 1][0] << "\n";
    // }
    // cout << "\n";
    for (int i = 1; i <= n; i++)
    {
        int idx = i, jdx = i;
        if (suf[i][1] > prf[i][1])
            idx--;
        else
            jdx++;
        //cout << suf[jdx][0] << " " << prf[idx][0] << '\n';
        mn = min(mn, max(suf[jdx][0], prf[idx][0]));
    }
    cout << mn;
}

• Subtask 1: 0 / 40
• Subtask 2: 0 / 60