Submission #1009355

#	Time	Username	Problem	Language	Result	Execution time	Memory
1009355		vjudge1	timeismoney (balkan11_timeismoney)	C++17	90 / 100	712 ms	900 KiB

timeismoney

#include <bits/stdc++.h>

using namespace std;

const int MAX = 205;
typedef long long ll;

struct Edge{
    int a, b, x, y;
};
struct Point{
    int x = 0, y = 0;
    vector<Edge> v = vector<Edge>{};
};
bool eq(Point& p1, Point& p2){
    return p1.x == p2.x && p1.y == p2.y;
}

int n, m, boss[MAX];
vector<Edge> edges;

int findBoss(int node){
    if(boss[node] == node) return node;
    return boss[node] = findBoss(boss[node]);
}

Point solve(int xCoeff, int yCoeff){
    for(int i = 0; i < n; i++) boss[i] = i;

    auto v = edges;
    sort(v.begin(), v.end(), [&](const Edge& e1, const Edge& e2){
         return (ll)xCoeff*e1.x + (ll)yCoeff*e1.y < (ll)xCoeff*e2.x + (ll)yCoeff*e2.y;
         });

    Point ret;
    ret.x = 0; ret.y = 0;
    for(auto e : v){
        int a = findBoss(e.a), b = findBoss(e.b);
        if(a == b) continue;

        if(rand() % 2) swap(a, b);
        boss[a] = b;

        ret.v.push_back(e);
        ret.x += e.x;
        ret.y += e.y;
    }

    return ret;
}

void print(Point& p){
    cout << p.x << ' ' << p.y << '\n';
    for(auto e : p.v) cout << e.a << ' ' << e.b << '\n';
}

Point best;
void rek(Point& a, Point& b){
    Point novi = solve(a.y - b.y, b.x - a.x);
    if(eq(a, novi) || eq(b, novi)) return;

    /*cout << "a\n";
    cout << a.x << ' ' << a.y << '\n';
    cout << "b\n";
    cout << b.x << ' ' << b.y << '\n';
    cout << "novi\n";
    cout << novi.x << ' ' << novi.y << '\n';*/
    if((ll)novi.x * novi.y < (ll)best.x * best.y) best = novi;

    rek(a, novi);
    rek(novi, b);
}

int main(){
    srand(time(0));

    cin >> n >> m;
    for(int i = 0; i < m; i++){
        Edge e;
        cin >> e.a >> e.b >> e.x >> e.y;
        edges.push_back(e);
    }

    Point minX = solve(1, 0);
    Point minY = solve(0, 1);

    best = minX;
    if((ll)best.x * best.y < (ll)minY.x * minY.y) best = minY;

    if(!eq(minX, minY)) rek(minX, minY);

    print(best);

    return 0;
}

• Subtask 1: 90 / 100