Submission #1007097

#	Time	Username	Problem	Language	Result	Execution time	Memory
1007097		Ludissey	Boxes with souvenirs (IOI15_boxes)	C++14	10 / 100	1 ms	348 KiB

boxes

#include "boxes.h"
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define sz(a) (int)a.size()
#define all(a) a.begin(), a.end()
int N,K,L;

int clst(int x){
    if(x>L/2) x=L-x;
    return (x)*2;
}

long long delivery(signed _n, signed _k, signed _l, signed p[]) {
    N=_n;
    K=_k;
    L=_l;
    vector<int> a(N);
    vector<int> marked(N);
    for (int i = 0; i < N; i++) a[i]=p[i];
    sort(all(a));
    int sumFULL=1e9;
    int sumNOTFULL=0;
    int lmt=N;
    vector<int> prf1(sz(a)+1,0);
    vector<int> prf2(sz(a)+1,0);
    lmt=sz(a);
    for (int i = 0; i < sz(a); i++) { if(a[i]>L/2) { lmt=i; break; } }
    for (int i = 0; i < N; i++) {
        if(i<K) prf1[i]=a[i]*2;
        else prf1[i]=a[i]*2+prf1[i-K];
    }
    for (int i = sz(a)-1; i >= 0; i--) {
        if(i>=sz(a)-K) prf2[i]=(L-a[i])*2;
        else prf2[i]=(L-a[i])*2+prf2[i+K];
    }
    for (int i = 0; i < sz(a); i++) {
        int res=L;
        if(i>0) res+=prf1[i-1];
        if(i<N-K) res+=prf2[i+K];
        sumFULL=min(sumFULL, res);
    }

    for (int i = lmt-1; i >= 0; i-=K) sumNOTFULL+=a[i]*2;
    for (int i = lmt; i < sz(a); i+=K) sumNOTFULL+=(L-a[i])*2;
    return min(sumFULL,sumNOTFULL);
}

• Subtask 1: 0 / 10
• Subtask 2: 10 / 10
• Subtask 3: 0 / 15
• Subtask 4: 0 / 15
• Subtask 5: 0 / 20
• Subtask 6: 0 / 30