This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "koala.h"
#include <vector>
using namespace std;
int minValue(int N, int W) {
// TODO: Implement Subtask 1 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
int B[105], R[105];
for(int i = 0; i < N; ++i) B[i] = (i == 0 ? 1 : 0);
playRound(B, R);
for(int i = 0; i < N; ++i) {
if(R[i] <= B[i]) return i;
}
return -1;
}
int maxValue(int N, int W) {
// TODO: Implement Subtask 2 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
int B[105], R[105], C[105];
for(int i = 0; i < N; ++i) C[i] = 1;
while(true) {
int rem = 0;
for(int i = 0; i < N; ++i) rem += C[i];
if(rem == 1) break;
for(int i = 0; i < N; ++i) {
B[i] = (C[i] ? W / rem : 0);
}
playRound(B, R);
for(int i = 0; i < N; ++i) {
if(C[i]) C[i] = (B[i] < R[i] ? 1 : 0);
}
}
for(int i = 0; i < N; ++i) {
if(C[i]) return i;
}
return -1;
}
int greaterValue(int N, int W) {
// TODO: Implement Subtask 3 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
return 0;
}
void allValues(int N, int W, int *P) {
if (W == 2*N) {
// TODO: Implement Subtask 4 solution here.
// You may leave this block unmodified if you are not attempting this
// subtask.
} else {
// TODO: Implement Subtask 5 solution here.
// You may leave this block unmodified if you are not attempting this
// subtask.
}
}
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