Submission #1000662

#TimeUsernameProblemLanguageResultExecution timeMemory
1000662BF001Training (IOI07_training)C++17
100 / 100
8 ms4956 KiB
#include <bits/stdc++.h> using namespace std; #define N 1005 #define int long long #define fi first #define se second #define log 10 typedef pair<int, int> pi; int n, dp[N][1 << 10], dep[N], tout[N], m, sum = 0, tin[N], tim, cnt[N], jmp[15][N]; vector<int> adj[N]; pi par[N]; struct iii{ int u, v, w; }; struct ii { int u, v, w, lca; bool operator < (ii& o){ return tout[lca] < tout[o.lca]; } }; vector<iii> vec; vector<ii> eg; void dfs(int u, int p){ tin[u] = ++tim; for (auto x : adj[u]){ if (x == p) continue; par[x] = {u, (1 << cnt[u])}; jmp[0][x] = u; cnt[u]++; dep[x] = dep[u] + 1; dfs(x, u); } tout[u] = ++tim; } bool in(int u, int v){ return (tin[u] <= tin[v] && tout[u] >= tout[v]); } int getlca(int u, int v){ if (in(u, v)) return u; if (in(v, u)) return v; for (int k = log; k >= 0; k--){ if (jmp[k][u] && !in(jmp[k][u], v)) u = jmp[k][u]; } return jmp[0][u]; } void dpp(){ for (auto x : eg){ int d1 = (dep[x.u] & 1); int d2 = (dep[x.v] & 1); if (d1 != d2 && x.w != 0) continue; int a = x.u, msk1 = 0, b = x.v, msk2 = 0; int sum = x.w; for (msk1 = 0; a != x.lca; msk1 = par[a].se, a = par[a].fi){ sum += dp[a][msk1]; } for (msk2 = 0; b != x.lca; msk2 = par[b].se, b = par[b].fi){ sum += dp[b][msk2]; } msk1 |= msk2; for (int msk = (1 << cnt[x.lca]) - 1; msk >= 0; msk--){ if (msk & msk1) continue; dp[x.lca][msk] = max(dp[x.lca][msk], sum + dp[x.lca][msk | msk1]); } } } signed main(){ ios_base::sync_with_stdio(0); cin.tie(NULL); cin >> n >> m; for (int i = 1; i <= m; i++){ int u, v, w; cin >> u >> v >> w; if (w == 0){ adj[u].push_back(v); adj[v].push_back(u); } sum += w; vec.push_back({u, v, w}); } par[1] = {1, 0}; dfs(1, 0); for (int k = 1; k <= log; k++){ for (int i = 1; i <= n; i++) jmp[k][i] = jmp[k - 1][jmp[k - 1][i]]; } for (auto x : vec){ int d1 = (dep[x.u] & 1); int d2 = (dep[x.v] & 1); if (d1 != d2 && x.w != 0) continue; int lca = getlca(x.u, x.v); eg.push_back({x.u, x.v, x.w, lca}); } sort(eg.begin(), eg.end()); dpp(); cout << sum - dp[1][0]; return 0; }
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